What is the magnitude of the electric field at the location of the test charge? (Answer ends in N/C)
A positive test charge of 4.0 x 10e-4 C is in an electric field that exerts a force of 2.5 x10e-4 N on it?
1.6 n/c
Reply:start with
F=qE
E=F/q=(2.6x10e-4)/4x10e-4)=0.65 N/C
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